Samurai Shodown 64 Download Pc LINK

Samurai Shodown 64 Download Pc LINK



Samurai Shodown 64 Download Pc

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The highlight of the game is that it supports playing 4 players simultaneously. It is Japan's first ever fighting game for the Playstation 4 to be the home version of the game, and. Samurai Shodown (2005) is known for the arcade playstyle and the

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Convert an input to a char in C

So I am creating a basic calculator. I want to take an input from the user using scanf() which is stored in an integer input. However, the input needs to be converted into a char.
I tried using atoi() which was pretty close to what I needed. I input 15 and I would expect the result to be c.
However the actual result was c.
Is there any way to do this without having to convert into a string?


Scanf takes a char*, and a format string that specifies how to read the data. It also takes additional arguments which are converted from their arguments into wide characters.

So you have to use %c and convert 15 to a c-style string.
int main(void)
int number = 15;
char *string;

string = malloc(11);
if (string == NULL)

if (scanf("%c", string)!= 1)

", string);
return 0;

Note: malloc is never required - but an error return from malloc means you didn't allocate enough.


I tried using atoi() which was pretty close to what I needed. I input 15 and I would expect the result to be c.

You don't need to use atoi at all. Atoi takes a char* buffer, and returns the value it finds at that point, which is a wide char. In other words, there's no char sequence there at all.
You can use scanf to get user input, and then convert it

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